The force applied against an object moving horizontally on a linear path is described by #F(x)= x+2 N #. By how much does the object's kinetic energy change as the object moves from # x in [ 1 , 3 ]#?

1 Answer
Apr 23, 2016

Chang in KE = work done against force=#int_1^3F(x)dx#
#=int_1^3(x+2)dx=[x^2/2+2x]_1^3#
#=3^2/2+2xx3-1^2/2-2xx1=8J#