What is #2/(x^2 - 9) + 3/(x^2-4x+3)#?

1 Answer
Shwetank Mauria
Apr 23, 2016

#2/(x^2-9)+3/(x^2-4x+3)=(5x+7)/((x-3)(x+3)(x-1))#

Explanation:

#2/(x^2-9)+3/(x^2-4x+3)#

= #2/((x-3)(x+3))+3/((x-3)(x-1))#

= #(2(x-1)+3(x+3))/((x-3)(x+3)(x-1))#

= #(2x-2+3x+9)/((x-3)(x+3)(x-1))#

= #(5x+7)/((x-3)(x+3)(x-1))#

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