Question

How do you find equation of line passing through the point (-1, 3) with slope m=2/3?

Answer 1

`y=2/3x+11/3`

Explanation:

By defining the gradient as a constant this is a straight line graph.

Standard form equation: `" "y=mx+c`

Where the gradient (slope) `->m = 2/3`
The line passes through the point `P_1->(x,y)=(-1,3)`

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`color(red)("Determine the value of c")`
Thus at `P_1" we have "color(brown)(y=m x+ c)color(green)(" "->3=2/3(-1)+c)`

`" "=>3=-2/3+c`

Add 2/3 to both sides

`" "3+2/3=-2/3+2/3+c`

`" "=>11/3=0+c`

`" "color(red)(c=11/3)`

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`color(blue)("Thus "y=mx+c" "->" "y=2/3x+11/3)`