How do you evaluate # Tan((3pi)/4)#?

Question

6702 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-25T15:31:55

#tan((3pi)/4)=-1#

#(3pi)/4=pi-pi/4#

#a=pi#

#b=pi/4#

#tan(a-b)=(tan a-tan b)/(1+tan a*tan b)#

#tan((3pi)/4)=(tan pi-tan (pi/4))/(1+tan pi*tan (pi/4)#

#tan((3pi)/4)=(0-1)/(1+0*1)#

#tan((3pi)/4)=-1/1#

#tan((3pi)/4)=-1#