How do you solve #6(x+4)-(x+3)=x-1#?

Question

1047 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-04-26T15:01:58

#color(green)(x = -11/2#

#6 ( x+4) - (x+3) = x-1#

#6 * ( x) + 6 * (4) - x - 3 = x-1#

#6x + 24 - x - 3 = x-1#

#6x - x - 3 + 24 = x-1#

#5x + 21 = x-1#

#5x -x = -1 - 21#

#4x = -22#

#x =- 22/4#

#x = -11/2#