How do you solve #(2[3(1/36)]-2)/((1/4)(-12) + 1)#?

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Answer 1 · 2016-04-27T05:53:09

#(2[3*(1/3*6)]-2)/((1/4)*(-12)+1)=-5#

#(2[3*(1/3*6)]-2)/((1/4)*(-12)+1)#

= #(2*[3*(1/cancel3*(2cancel6)]-2))/((1/(1cancel4)*(-3cancel1))+1)#

= #(2*[3*2]-2)/(-3+1)#

= #(2*6-2)/(-2)#

= #10/(-2)=-5#

How do you solve #(2[3*(1/3*6)]-2)/((1/4)(-12) + 1)#?