How do you solve #30-5(4^2-8÷4-5*2)#?

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Answer 1 · 2016-04-28T14:39:47

#10#

According to B.E.D.M.A.S., simplify the expression within the brackets. Start by simplifying the exponents.

#30-5(color(red)(4^2)-8-:4-5*2)#

#=30-5(color(red)(16)# #color(blue)(-8-:4)-5*2)#

Multiply/divide the numbers from left to right within the brackets.

#=30-5(16# #color(blue)(-2)# #color(darkorange)(-5*2))#

#=30-5(color(teal)(16-2)# #color(darkorange)(-10))#

Subtract the numbers from left to right within the brackets.

#=30-5(color(teal)14-10)#

#=30# #color(purple)(-5(4))#

Multiply #-5# by #4#.

#=30# #color(purple)(-20)#

#=10#