A container with a volume of #5 L# contains a gas with a temperature of #320^o K#. If the temperature of the gas changes to #240^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-04-28T18:11:37

#V_2=3,75 L#

#"first volume: " V_1=5L#
#"first temperature :"T_1=320^o K#

#"last temperature :"T_2=240^o K#
#"last volume :"V_2=?#

#V_1/T_1=V_2/T_2#

#V_2=(V_1*T_2)/T_1#

#V_2=(5*240)/320#

#V_2=3,75 L#