Question

Question #85638

Answer 1

`x =-(log 3 - log 2 )/log 3=-0.3691`, nearly.

Explanation:

Use`(ab)^n=a^nb^n, a^(m+n)=a^ma^n and log(a^n)=n log a`

`((3)(2))^(x+1)=3^(x+1)2^(x+1)=2^(x+2)`.

So, `3^(x+1)=2`.

Equating logarithms and simplifying,

`x =-(log 3 - log 2 )/log 3=-0.3691`, nearly.