Question

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

Answer 1

Over `40*atm`. We follow the ideal gas equation

Explanation:

`P=(nRT)/V` `=` `(1*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx1000*cancel(K))/(2.00*cancelL)` `=` `??*atm`

I hope the container is strong.