How do you solve for x in #y=mx+b#?

1 Answer
Alan P.
May 2, 2016

#x=(y-b)/m# (with the obvious restriction #m!=0#)

Explanation:

If
#color(white)("XXX")y=mx+b#

subtracting #b# from both sides
#color(white)("XXX")y-b=mx#

dividing both sides by #m#
#color(white)("XXX")(y-b)/m=x#

flipping the sides (to make it look more normal)
#color(white)("XXX")x=(y-b)/m#

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