Question

How much heat is required to warm 1.60 kg of sand from 22°C to 100°C?

Answer 1

The energy required to heat the sand by `78^@"C"` is `~~` `"36000 J"`.

Explanation:

The specific heat capacity for sand, `c`, is `"0.290 J/g"^@"C"`.
http://www2.ucdsb.on.ca/tiss/stretton/database/Specific_Heat_Capacity_Table.html

The equation for determining the heat required to increase the temperature of the sand is `Q=cmDeltaT`, where `Q` is heat energy in Joules, `m` is mass in grams, `c` is specific heat capacity, and `Delta T` is the change in temperature, `(T_"final"-T_"initial")`.

`Delta T=(100^@"C")-(22^@"C")=78^@"C"`

Mass of sand in grams:

`1.60cancel"kg"xx(1000"g")/(1cancel"kg")="1600 g"`

Substitute the given values into the equation.

`Q=(0.290"J/g"^@"C")xx(1600"g")xx(78^@"C")="36000 J"` (rounded to two significant figures)