Question

How do you solve `log_b(5)=0.558`?

Answer 1

I found `b=e^2.8843=17.89~~18`

Explanation:

I would try changing base to your log choosing the natural log, i.e., `ln`:

`(ln(5))/(ln(b))=0.558`
so rearranging:
`ln(b)=(ln(5))/(0.558)=2.8843`
now we apply the definition of log to get:
`b=e^2.8843=17.89~~18`