A triangle has corners at points A, B, and C. Side AB has a length of #24 #. The distance between the intersection of point A's angle bisector with side BC and point B is #6 #. If side AC has a length of #16 #, what is the length of side BC?

1 Answer
May 3, 2016

10

Explanation:

Here is a sketch (not to scale)

enter image source here

To calculate BC we require the length of DC.

Using the #color(blue)" Angle bisector theorem "#

#color(red)(|bar(ul(color(white)(a/a)color(black)( (BD)/(DC)=(AB)/(AC))color(white)(a/a)|)))#

Substitute the appropriate values into the ratio.

hence #6/(DC)=24/16#

now cross-multiply

#rArr 24xxDC=16xx6rArr DC=(16xx6)/24=4#

Now BC = BD + DC = 6 + 4 = 10