Question

Question #3a473

Answer 1

see below

Explanation:

Right Side:`=cosx/(1-sinx) xx (1+sinx)/(1+sinx)`

`=(cosx(1+sinx))/(1-sin^2x)`

`=(cosx(1+sinx))/cos^2x`

`=(1+sinx)/cos x`

`=1/cosx + sinx /cosx`

`=secx + tanx`

`=` Left Side