How do you verify #tanh x/(cosh x - sinh x tanh x) = sinh x#?

Question

1778 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-05T20:35:40

see below

Left Side: #=(sinhx/coshx)/(coshx-(sinhx*sinhx/coshx)#

#=(sinhx/coshx)/(coshx-sinh^2x/(coshx))#

#=(sinhx/coshx)/((cosh^2x-sinh^2x)/(coshx))#

#=sinhx/coshx * coshx/(cosh^2x-sinh^2x)#

#=sinhx/(cosh^2x-sinh^2x)#

#=sinhx/1#

#=sinhx#

#=# Right Side