How do you solve #2x-y=-10# and # 2x-4y=-4#? Precalculus Matrix Row Operations Solving a System of Equations Using a Matrix 1 Answer ali ergin May 6, 2016 #x=-5/2# #y=-2# Explanation: #2x-y=-10" "color(red)(2x)=y-10" (1)"# #2x-4y=-4" "color(red)(2x)=4y-4" (2)"# #(1)=(2)# #y-10=4y-4# #-10+4=4y-y# #-6=3y# #y=-6/3# #y=-2# #"using (1) or (2)"# #2x=y-3# #2x=-2-3# #2x=-5# #x=-5/2# Answer link Related questions How do I use matrices to solve the system #2x+3y=4# and #5x+8y=11#? How do I solve a system of equations using an augmented matrix? How do I solve a system of 3 equations with a matrix? How do I solve a system of equations using inverse matrices? How do I solve a system of 2 equations using a matrix? How do I use matrices to find the solution of the system of equations #3x+4y=10# and #x-y=1#? How do I use matrices to find the solution of the system of equations #c+3d=8# and #c=4d-6#? How do I use matrices to find the solution of the system of equations #y=1/3x+7/3# and #y=−5/4x+11/4#? How do I use matrices to find the solution of the system of equations #y=−2x+4# and #y=−2x−3#? How do I use matrices to find the solution of the system of equations #y=−2x−4# and #y+4=−2x#? See all questions in Solving a System of Equations Using a Matrix Impact of this question 1731 views around the world You can reuse this answer Creative Commons License