Question

How do you solve `3x^2 − 6 = 4x` using the quadratic formula?

Answer 1

When you are solving a quadratic equation, make it equal to 0.
`x = (4+sqrt88)/6` or `x= (4-sqrt88)/6`

Explanation:

`3x^2 - 4x - 6 = 0` `" "` `rArr a = 3, b = -4, c = -6`

`x = [-b +-sqrt(b^2 - 4ac)]/(2a)`

`x = [-(-4) +-sqrt((-4)^2 - 4(3)(-6))]/(2(3))`

`x = [4 +-sqrt(16 + 72)]/(6)`

`x = (4+sqrt88)/6` or `x= (4-sqrt88)/6`