If an object with uniform acceleration (or deceleration) has a speed of #3 m/s# at #t=0# and moves a total of 8 m by #t=4#, what was the object's rate of acceleration?

Question

1528 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-05-07T06:22:24

Deceleration of #-0.25 m/s^2#

At time #t_i=0# it had initial velocity of #v_i=3m/s#

At time #t_f=4# it had covered #8 m#

So
google

#v_f=8/4#

#v_f=2m/s#

Rate of acceleration is determined from

google

#a=(v_f-v_i)/(t_f-t_i)#

#a=(2-3)/(4-0)#

#a=-1/4##m/s^2#

#a=-0.25 m/s^2#

As #a# is negative we take it as deceleration of #-0.25 m/s^2#

Cheers