Question

How do you solve `log_3 (2x + 1) = log_3 (x - 4)`?

Answer 1

We have that

# log_3 (2x + 1) = log_3 (x - 4)=> (2x+1)=(x-4)=>2x-x=-1-4=>x=-5#

But hence it should be `x>4` there no real solutions.