Question

How do you solve `log _(x+2) 1000 = 3`?

Answer 1

`x =8`.

Explanation:

Use inversion `a =b^c` for `c=log_b a`.

Here, `1000=(x+2)^3`

So, `x+2=1000 ^(1/3)=(10^3)^(1/3)=10^((1/3)(3))=10^1=10`

x=8..