A container with a volume of #4 L# contains a gas with a temperature of #360^o K#. If the temperature of the gas changes to #120^o K# without any change in pressure, what must the container's new volume be?

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Answer 1 · 2016-05-09T10:04:12

#V_2=4/3 L#

#V_1=4L#
#V_2=?#

#T_1=360^o K#
#T_2=120^o K#

#V_1/T_1=V_2/T_2#

#4/360=V_2/120#

#V_2=(120*4)/360#

#V_2=4/3 L#