Question

How do you solve for a in `c = 8πab`?

Answer 1

`color(blue)(a =c /( 8 pi b )`

Explanation:

`c = 8 pi a b`

`c = 8 pi color(blue)(a) b`

Isolating `color(blue)(a)`:

`c = 8 pi b * color(blue)(a)`

`color(blue)(a =c /( 8 pi b )`