Question

What is the Cartesian form of `(10,(-7pi)/3))`?

Answer 1

`x=5`
`y=-5sqrt3`

Explanation:

The given data `(r, theta)=(10, (-7pi)/3)`

`x=r cos theta=10*cos ((-7pi)/3)=10*cos (-pi/3)=10*(1/2)`
`x=5`
`y=r sin theta+10*sin ((-7pi)/3)=10*sin (-pi/3)=10((-sqrt3)/2)`
`y=-5sqrt3`

God bless....I hope the explanation is useful.