Question

If `8 L` of a gas at room temperature exerts a pressure of `25 kPa` on its container, what pressure will the gas exert if the container's volume changes to `5 L`?

Answer 1

`P_f=40L`

Explanation:

`"initial volume :"V_i=8L`
`"initial pressure:"P_i=25kPa`

`"final volume:"V_f=5L`
`"final pressure:"P_f=?`

`P_i*V_i=P_f*V_f" Boyle's Law"`

`25*8=P_f*5`

`P_f=200/5`

`P_f=40L`