Question

How do you solve `log_7 (x+3) - 2 = log_7 3`?

Answer 1

`x=40/3`

Explanation:

Use log m + log m = log (mn).

Here, `log_7(x+3)+log_7 3= log_7(3(x+3))=2`.

Use that if `c=log_b a, a=b^c`.

Accordingly, `3(x+3)=7^2=49`.

So, `x = 40/3`.