What is the average speed of an object that is moving at 5 m/s at t=0 and accelerates at a rate of a(t) =t-4 on t in [4,5]?

1 Answer
May 11, 2016

v_a=17/6" " m/s

Explanation:

(d v)/(d t)=a(t)

d v=a(t)*d t

int d v=int a(t)* d t

v=int (t-4)*d t

v=t^2/2-4t +C " "t=0 ;v=5 m/s" ; "c=5 m/s

v=t^2/2-4t+5

(d x)/(d t)=v(t)

d x=v(t)*d t

int d x=int _4^5 v(t)*d t

x=int_4^5 (t^2/2-4t+5)d t

x=|1/2*t^3/3-4*t^2/2+5*t|_4^5

x=(1/2*5^3/3-2*5^2+5*5)-(1/2*4^3/3-2*4^2+5*4)

x=125/6-50+25)-(64/6-32+20)

x=125/6-25-64/6+12=61/6-13

x=(61-78)/6

x=|-17/6|

x=17/6 meters

v_a=x/t

v_a=(17/6)/(5-4)

v_a=17/6" " m/s