Question

How do you factor `y^2+6y +8`?

Answer 1

see below

Explanation:

Let `y^2+by+c`

First, we must take the product of value of c and sum of value of b.

For example in this question, the value of product is 8 and value of sum is 6.

Then it can be 2 and 4 or 2 and -4 or -4 and 2 or -4 and -2
and,
If sum is +6 then it can be (4+2)=6, but other cannot since it produced -6

And product, since (4).(2)=8,
then.

the factorization for `y^2+6y+8` is `(y+2)(y+4)`