What is the cross product of [3,1,-5][3,1,5] and [2, -1, 1] [2,1,1]?

1 Answer
May 12, 2016

AXB=-4i-13j-5kAXB=4i13j5k

Explanation:

vec A=[3,1,-5]A=[3,1,5]

vec B=[2,-1,1]B=[2,1,1]

A_x=3Ax=3
A_y=1Ay=1
A_z=-5Az=5

B_x=2Bx=2
B_y=-1By=1
B_z=1Bz=1

AXB=(A_y*B_z-A_z*B_y)i-(A_x*B_z-A_z*B_x)j+(A_x*B_y-A_y-B_x)kAXB=(AyBzAzBy)i(AxBzAzBx)j+(AxByAyBx)k

AXB=i(1*1-(5*1))-j(3*1+2*5)+k(-1*3-2*1)AXB=i(11(51))j(31+25)+k(1321)

AXB=i(1-5)-j(3+10)+k(-3-2)AXB=i(15)j(3+10)+k(32)

AXB=-4i-13j-5kAXB=4i13j5k