Question

How do you solve `2sinx cosx-sqrt3 cosx=0`?

Answer 1

`pi/2, (3pi)/2, pi/3 and (2pi)/3` for `(0, 2pi)`

Explanation:

`2sin x.cos x - sqrt3cos x = 0`
`cos x(2sin x - sqrt3) = 0`
Trig table and unit circle -->
a. cos x = 0 --> `x = pi/2` and `x = (3pi)/2`
b. `sin x = sqrt3/2` --> `x = pi/3` and `x = (pi - pi/3) = (2pi)/3`