An object is at rest at #(8 ,2 ,5 )# and constantly accelerates at a rate of #7/4 m/s^2# as it moves to point B. If point B is at #(6 ,5 ,1 )#, how long will it take for the object to reach point B? Assume that all coordinates are in meters.

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Answer 1 · 2016-05-14T07:22:33

time #t=2.480821248" "#seconds

Given object at rest
#v_0=0" "#initial velocity

distance traveled by the object
#s=sqrt((x_B-x_A)^2+(y_B-y_A)^2+(z_B-z_A)^2)#
#s=sqrt((6-8)^2+(5-2)^2+(1-5)^2)#
#s=sqrt(4+9+16)#
#s=sqrt(29)#

the formula to compute t

#s=v_0t+1/2at^2#
#sqrt(29)=(0)*t+1/2(7/4)t^2#
#t^2=8/7sqrt29#
#t=(8/7sqrt29)^(1/2)#

#t=2.480821248" "#seconds

God bless....I hope the explanation useful