A current of 3.03 A is passed through a $Pb(NO_3)_2$ solution for 1.20 hours. How much lead is plated out of the solution?

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Answer 1 · 2016-05-14T14:26:17

$~~14g$

We know from Faraday;s law of electrolysis the mass of a substance (in g ) deposited at any electrode is given by

$w =(Ect)/F" "$ where

$E= "equivalent mass of ion "Pb^(2+) ="molar mass"/"valency"=207/2=103.5g/"equivalent "$
$c=Current=3.03A$
$t =Time=1.2hrs=1.2xx60xx60s=4320s$
$F=96500C$
$w =(Ect)/F=(103.5xx3.03xx4320)/96500g~~14g$

A current of 3.03 A is passed through a Pb(NO_3)_2Pb(NO_3)_2 solution for 1.20 hours. How much lead is plated out of the solution?