Question

How do you solve `1.60= y/( 0.200 - y )( 0.100 - y )`?

Answer 1

I found:
two solutions:
`y_1=1.48`
`y_2=0.21`

Explanation:

We could write:
`1.6=16/10`
`0.2=2/10`
and
`0.1=1/10`
to write it as:
`16/10=y/(2/10-y)(1/10-y)`
Rearranging:
`16/10(2/10-y)=y(1/10-y)`
and:
`16(2/10-y)=10y(1/10-y)`
`32/10-16y=y-10y^2`
`10y^2-17y+16/5=0`
`50y^2-85y+16=0`
Using the Quadratic Formula:
`y_(1,2)=(85+-sqrt(7225-3200))/100=`
`=(85+-sqrt(4025))/100=`
two solutions:
`y_1=1.48`
`y_2=0.21`