Question

How do you find the derivative of `ln(x+y) = x^2`?

Answer 1

`y'=2 x e^(x^2) -1`

Explanation:

The inverse relation is `x + y = e^(x^2)`.

Term-by-term differentiation gives

`1 + y'=2 x r^(x^2)`, applying function of function rule..

So, `y'=2 x e^(x^2) -1`