How do you evaluate #18^(x-2) = 13^(-2x)#? Precalculus Solving Exponential and Logarithmic Equations Logarithmic Models 1 Answer Cesareo R. May 15, 2016 #x = (2 log(18))/(2 log(13) + log(18))# Explanation: Applying #log# to each equation side #(x-2)log(18)=-2x log(13)# solving for #x# gives #x = (2 log(18))/(2 log(13) + log(18))# Answer link Related questions What is a logarithmic model? How do I use a logarithmic model to solve applications? What is the advantage of a logarithmic model? How does the Richter scale measure magnitude? What is the range of the Richter scale? How do you solve #9^(x-4)=81#? How do you solve #logx+log(x+15)=2#? How do you solve the equation #2 log4(x + 7)-log4(16) = 2#? How do you solve #2 log x^4 = 16#? How do you solve #2+log_3(2x+5)-log_3x=4#? See all questions in Logarithmic Models Impact of this question 1275 views around the world You can reuse this answer Creative Commons License