A container with a volume of 15 L contains a gas with a temperature of 290^o K. If the temperature of the gas changes to 350 ^o K without any change in pressure, what must the container's new volume be?

2 Answers

approx18.1L.

Explanation:

According to ideal gas law,

P*V=n*R*T

Since,
P, n, R are constant throughout the process,

V/T=(n*R)/P=constant

Therefore,

VpropT

V_"initial"/T_"initial"=V_"final"/T_"final"

So,
V_"final"=(V_"initial"*T_"final")/T_"initial"=(15*350)/290approx18.1L

The answer is 18.1L

May 15, 2016

V_2=18.1 L

Explanation:

P="constant"
V_1=15L
T_1=290 ^o K

T_2=350 ^o K
V_2=?

V_1/T_1=V_2/T_2

15/290=V_2/350

V_2=(15*350)/290

V_2=18.1 L