If a pure R isomer has a specific rotation of –142.0°, and a sample contains 77.0% of the R isomer and 23.0% of its enantiomer, what is the observed specific rotation of the mixture?
1 Answer
May 16, 2016
The observed specific rotation of the mixture is -76.7 °.
Explanation:
The rotations of the two enantiomers cancel each other, so the rotation of the mixture is that of the excess enantiomer.
The enantiomeric excess (
∴ The observed rotation is 54.0 % that of the