What is #(2+76-:1+9) + 4-3*9#?

2 Answers
May 16, 2016

#(2+76-:1+9)+4-3*9=64#

Explanation:

In solving #(2+76-:1+9)+4-3*9# according to PEMDAS, parentheses should be solved first, but within parentheses one should divide first and then do addition.

Hence #(2+76-:1+9)+4-3*9#

= #(2+76+9)+4-3*9# and now multiplication first

= #87+4-27#

= #64#

Observe that within parentheses, division / multiplication is performed before addition or subtraction.

Oct 1, 2017

#64#

Explanation:

In an expression which has different operations always count the number of TERMS first.

Each term is simplified to a single answer and these are added and subtracted in the last step

Within each term, the order is:
- brackets
- powers and roots
- multiply and divide

When you have the final value for each term, then:
- add and subtract

It is a good idea to move the additions to the front of the expression and do them first, and move the subtractions to the end.

#" "color(red)((2+76-:1+9))" "color(blue)(+4)" "color(green)(-3xx9)" "larr# there are #3# terms
#color(white)(xxx.xx)darr#
#= color(red)((2+76+9))" "color(blue)(+4)" "color(green)(-27)#

#= color(red)(87" "color(blue)(+4)" "color(green)(-27)#

#=91-27#

#=64#