Question #2bbce

May 19, 2016

Assuming #cos(x)!=0# and #sin(x)!=0#, using the identity #csc^2(x)=1+cot^2(x)#, we have

#csc^2(x)tan^2(x)-1 = (1+cot^2(x))tan^2(x)-1#

#=tan^2(x)+cot^2(x)tan^2(x)-1#

#=tan^2(x)+(cot(x)tan(x))^2-1#

#=tan^2(x)+1^2-1#

#=tan^2(x)#

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