A line passes through (3, -2)(3,2) and (8, 2)(8,2). How do you write an equation for the line in point-slope form? What about in standard form?

1 Answer
May 19, 2016

Point-slope form: y=4/5x-22/5y=45x225
Standard form: 4x-5y=224x5y=22

Explanation:

First we calculate the slope(SS)=(2-(-2))/(8-3)=2(2)83
Point-slope form: y=Sx+k=4/5x+ky=Sx+k=45x+k bring in (3, -2) or (8, 2)(3,2)or(8,2) to solve kk, you'll get k=22/5k=225
So point slope form is y=4/5x-22/5y=45x225
Standard form: ax+by=cax+by=c
y=4/5x-22/5 ->5y=4x-22->4x-5y=22y=45x2255y=4x224x5y=22