A line passes through $(3, - 2)$ $(3, -2)$ and $(8, 2)$ $(8, 2)$ . How do you write an equation for the line in point-slope form? What about in standard form?

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A line passes through $(3, - 2)$ $(3, -2)$ and $(8, 2)$ $(8, 2)$ . How do you write an equation for the line in point-slope form? What about in standard form?

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Answer 1 · 2016-05-19T02:37:23

Point-slope form: $y = \frac{4}{5} x - \frac{22}{5}$ $y=4/5x-22/5$
Standard form: $4 x - 5 y = 22$ $4x-5y=22$

Explanation:

First we calculate the slope( $S$ $S$ ) $= \frac{2 - (- 2)}{8 - 3}$ $=(2-(-2))/(8-3)$
Point-slope form: $y = S x + k = \frac{4}{5} x + k$ $y=Sx+k=4/5x+k$ bring in $(3, - 2) or (8, 2)$ $(3, -2) or (8, 2)$ to solve $k$ $k$ , you'll get $k = \frac{22}{5}$ $k=22/5$
So point slope form is $y = \frac{4}{5} x - \frac{22}{5}$ $y=4/5x-22/5$
Standard form: $a x + b y = c$ $ax+by=c$
$y = \frac{4}{5} x - \frac{22}{5} \to 5 y = 4 x - 22 \to 4 x - 5 y = 22$ $y=4/5x-22/5 ->5y=4x-22->4x-5y=22$

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A line passes through $(3, - 2)$ $(3, -2)$ and $(8, 2)$ $(8, 2)$ . How do you write an equation for the line in point-slope form? What about in standard form?

1 Answer

Explanation:

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A line passes through (3, -2)(3,−2)(3, -2) and (8, 2)(8,2)(8, 2). How do you write an equation for the line in point-slope form? What about in standard form?

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Explanation:

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A line passes through $(3, - 2)$ $(3, -2)$ and $(8, 2)$ $(8, 2)$ . How do you write an equation for the line in point-slope form? What about in standard form?