A line passes through (3, -2) and (8, 2). How do you write an equation for the line in point-slope form? What about in standard form?

1 Answer
Daniel K.
May 19, 2016

Point-slope form: y=4/5x-22/5
Standard form: 4x-5y=22

Explanation:

First we calculate the slope(S)=(2-(-2))/(8-3)
Point-slope form: y=Sx+k=4/5x+k bring in (3, -2) or (8, 2) to solve k, you'll get k=22/5
So point slope form is y=4/5x-22/5
Standard form: ax+by=c
y=4/5x-22/5 ->5y=4x-22->4x-5y=22

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