A line passes through #(3, -2)# and #(8, 2)#. How do you write an equation for the line in point-slope form? What about in standard form?

1 Answer
Daniel K.
May 19, 2016

Point-slope form: #y=4/5x-22/5#
Standard form: #4x-5y=22#

Explanation:

First we calculate the slope(#S#)#=(2-(-2))/(8-3)#
Point-slope form: #y=Sx+k=4/5x+k# bring in #(3, -2) or (8, 2)# to solve #k#, you'll get #k=22/5#
So point slope form is #y=4/5x-22/5#
Standard form: #ax+by=c#
#y=4/5x-22/5 ->5y=4x-22->4x-5y=22#

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