What volume of #NaOH(aq)# at #0.75molL^-1# concentration is required to neutralize a #275mL# volume of #H_2SO_4(aq)# whose concentration is #0.50mol*L^-1#?

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Answer 1 · 2016-05-19T06:14:28

Approx. #400*mL#

#2NaOH(aq) + H_2SO_4(aq) rarr Na_2SO_4(aq) + 2H_2O(l)#

There is a #2:1# stoichiometry between between caustic soda and sulfuric acid.

#"Moles of sulfuric acid"# #=# #0.50*mol*L^-1xx0.275*L# #=# #0.138*mol#.

Thus #0.275*mol# #"sodium hydroxide"# are required.

#(0.275*cancel(mol))/(0.75*cancel(mol*L^-1))xx10^3*mL*cancelL^-1# #=# #??*mL#

What volume of #NaOH(aq)# at #0.75*mol*L^-1# concentration is required to neutralize a #275*mL# volume of #H_2SO_4(aq)# whose concentration is #0.50*mol*L^-1#?