How do you solve #-3/4 x = 12#?

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Answer 1 · 2016-05-19T13:14:57

convert #-3/4# into a decimal, then divide #12/-0.75#

#-3/4= 3-:4=-0.75#

#12/-0.75=-16#

#x=-16#

Because #-0.75xx-16=12#

Answer 2 · 2016-05-19T13:21:47

#x=-16#

Multiply both sides by #color(blue)(4/3)#

#color(brown)(-3/4x=12" "->" "-(3/4color(blue)(xx4/3))xx x= 12color(blue)(xx4/3))#

But #3/4xx4/3 = 1#

#-1xx x=16#

Multiply both sides by #(-1)#

#+1xx x = -16#

#x=-16#