How do you solve x^2 - 3x + 1 = 0? Algebra Quadratic Equations and Functions Comparing Methods for Solving Quadratics 1 Answer Nicole May 20, 2016 (3±sqrt(5))/(2) Explanation: Use the quadratic formula (-b±sqrt(b^2-4ac))/(2a) a=1 b=-3 c=1 (3±sqrt(-3^2-4xx1xx1))/(2xx1) = (3±sqrt(5))/(2) Answer link Related questions What are the different methods for solving quadratic equations? What would be the best method to solve -3x^2+12x+1=0? How do you solve -4x^2+4x=9? What are the two numbers if the product of two consecutive integers is 72? Which method do you use to solve the quadratic equation 81x^2+1=0? How do you solve -4x^2+4000x=0? How do you solve for x in x^2-6x+4=0? How do you solve x^2-6x-16=0 by factoring? How do you solve by factoring and using the principle of zero products x^2 + 7x + 6 = 0? How do you solve x^2=2x? See all questions in Comparing Methods for Solving Quadratics Impact of this question 1329 views around the world You can reuse this answer Creative Commons License