How do you find an equation of a line containing the point (3, 2), and perpendicular to the line y - 2 = (2/3)x?

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Answer 1 · 2016-05-21T05:48:07

#y=-3/2 x+13/2#

Given -

#y-2=2/3 x#

Rewrite it -

#y=2/3 x+2#

Its Slope #m_1=2/3#

Two lines are perpendicular if -

#m_1 xx m_2 = -1#

Find the slope of the perpendicular line

#2/3 xx m_2= -1#
#m_2= -1 xx 3/2=-3/2#

The perpendicular line is passing through the point #(3,2)#

Its equation is -

#y-y_1=m2(x-x_1)#
#y-2=-3/2(x-3)#
#y=-3/2x+9/2+2#
#y=-3/2 x+13/2#