How do you solve using the quadratic formula method #4x^2 + 2 = 7x#?

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Answer 1 · 2016-05-21T11:42:51

The solutions for the quadratic equation are:

#color(blue)(x =(7+sqrt(17))/8#

#color(blue)(x =(7-sqrt(17))/8#

#4x^2 + 2 = 7x#

#4x^2 - 7x + 2 = 0#

The equation is of the form #color(blue)(ax^2+bx+c=0# where:
#a=4, b=-7, c=2#

The Discriminant is given by:

#Delta=b^2-4*a*c#

# = (-7)^2-(4* 4 * 2)#

# = 49 - 32 = 17 #

The solutions are found using the formula
#x=(-b+-sqrtDelta)/(2*a)#

#x = (-(-7)+-sqrt(17))/(2*4) = (7+-sqrt(17))/8#

#x =(7+sqrt(17))/8#

#x =(7-sqrt(17))/8#