Question

If the length of a `48` `cm` spring increases to `93` `cm` when a `6` `kg` weight is hanging from it, what is the spring's constant?

Answer 1

First, we need to work in SI units - meters, not centimeters.

The length increases from `0.48` `m` to `0.93` `m`. The force acting is the weight force, `F=mg=6*9.8=58.8` `N`.

Then `k=F/x=58.8/(0.93-0.48)~~130.7` `Nm^-1` (or `kgs^-2`).