Question

What is the derivative of `(x^2-1)^3/(x^2+1)`?

Answer 1

`(d y)/(d x)=-2x*(x^2-1)^3/(x^2+1)^2+6x(x^2-1)^2/(x^2+1`

Explanation:

`d/(d x)(x^2-1)^3/(x^2+1)=?`

`d/(d x) (x^2-1)^3/(x^2+1) = (3(x^2-1)^2*2x*(x^2+1)-2x(x^2-1)^3)/(x^2+1)^2`

`d/(d x)(x^2-1)^3/(x^2+1)=-2x*(x^2-1)^3/(x^2+1)^2+6x(x^2-1)^2/(x^2+1)`