Question #9387b
1 Answer
May 22, 2016
First simplify
#100int_0^1x^9f(x^10)dx=100/10int_0^1f(x^10)10x^9dx=10int_0^1f(u)du#
Note that the bounds did change, but not noticeably, since
Also note that
So, we see the value of
#"....."+100int_0^1x^9f(x^10)dx="....."+10int_0^1f(x)dx="....."+50#
I'm not really sure what the