Question

How do you find the center and radius of the circle `x^2 + y^2 - 12x - 8y + 48 = 0`?

Answer 1

Write this as follows

`x^2 + y^2 - 12x - 8y + 48 = 0`

`(x^2-12x+36)+(y^2-8y+16)+48-36-16=0`

`(x-6)^2+(y-4)^2=4`

`(x-6)^2+(y-4)^2=2^2`

From this we get the center which is point `(6,4)` and radius `r=2`