How do you find $| - 4 + 3 i |$ $abs(-4 + 3i)$ ?

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Answer 1 · 2016-05-23T14:03:06

$| - 4 + 3 i | = 5$ $|-4+3i|=5$

Absolute value of a complex number $a + i b$ $a+ib$ is denoted as $| a + i b |$ $|a+ib|$

and is given by $\sqrt{a^{2} + b^{2}}$ $sqrt(a^2+b^2)$

Hence absolute value $| - 4 + 3 i |$ $|-4+3i|$ is

$\sqrt{4^{2} + 3^{2}} = \sqrt{16 + 9} = \sqrt{25} = 5$ $sqrt(4^2+3^2)=sqrt(16+9)=sqrt25=5$

How do you find |−4+3i|abs(-4 + 3i)?